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关于arctanyx的时尚顾问

arctany/x求偏导

  • arctany/x求偏导

  • 偏导为：-2xy/(x²+y²)²解:原式=∂z/∂x=1/(1+y²/x²)*(-y/x²)=-y/(x²+y²)∂z/∂y=1/(1+y²/x²)*1/x=x/(x²+y²)∂²z/∂x²=y/(x²+y²)*2x=2xy/(x²+y²)²∂²z/∂x∂y=-[x²+y²-2y²]/(x²+y²)²=(y²-x²)/(x²+y²)²∂²z/∂y²=-2xy/(x²+y²)²[arctany...
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